What is 1st order homogenous differential equation?The ODE is homogeneous ODE of order one This is because the coefficients of dx and dy are both homogeneous two variables functions of the same order I suggest you write the ODE as y′ = 32t2t2−t−2 = f (t), (x = 0,t = y/x) Find the solution of (xy^22x^2y^3)dx (x^2yx^3y^2)dy=0 Find the solution of (xy2 2x2y3)dx (x2y −x3y2Given, (x 2y 2)dx−2xydy=0 ⇒(x 2y 2)dx=2xydy ⇒ dxdy= 2xyx 2y 2 (i) Let y=vx Thus, dxdy=vx dxdv Thus, vx dxdv= 2x(vx)x 2(vx) 2 ⇒vx dxdv= 2v1v 2 ⇒x dxdv= 2v1v 2−v
Solve The Differential Equation X2 Y2 Dx 2xydy 0 Given Y 0 X 1 Maths Differential Equations Meritnation Com
